Solve for a2 a_2=(2^2-10)/(2^2+10)

$a_{2} = \frac{2^{2} - 10}{2^{2} + 10}$

Simplify the numerator.

Raise $2$ to the power of $2$ .

$a_{2} = \frac{4 - 10}{2^{2} + 10}$

Subtract $10$ from $4$ .

$a_{2} = \frac{- 6}{2^{2} + 10}$

Simplify the denominator.

Raise $2$ to the power of $2$ .

$a_{2} = \frac{- 6}{4 + 10}$

Add $4$ and $10$ .

$a_{2} = \frac{- 6}{14}$

Reduce the expression by cancelling the common factors.

Cancel the common factor of $- 6$ and $14$ .

Factor $2$ out of $- 6$ .

$a_{2} = \frac{2 (- 3)}{14}$

Cancel the common factors.

Factor $2$ out of $14$ .

$a_{2} = \frac{2 \cdot - 3}{2 \cdot 7}$

Cancel the common factor.

$a_{2} = \frac{2 \cdot - 3}{2 \cdot 7}$

Rewrite the expression.

$a_{2} = \frac{- 3}{7}$

Move the negative in front of the fraction.

$a_{2} = - \frac{3}{7}$

The result can be shown in multiple forms.

Exact Form:

$a_{2} = - \frac{3}{7}$

Decimal Form:

$a_{2} = - 0.\overline{428571}$