Solve for a2 a_2=(2^2-9)/(2^2+9)

$a_{2} = \frac{2^{2} - 9}{2^{2} + 9}$

Step 1

Simplify the numerator.

Raise $2$ to the power of $2$ .

$a_{2} = \frac{4 - 9}{2^{2} + 9}$

Subtract $9$ from $4$ .

$a_{2} = \frac{- 5}{2^{2} + 9}$

$a_{2} = \frac{- 5}{2^{2} + 9}$

Step 2

Simplify the denominator.

Raise $2$ to the power of $2$ .

$a_{2} = \frac{- 5}{4 + 9}$

Add $4$ and $9$ .

$a_{2} = \frac{- 5}{13}$

$a_{2} = \frac{- 5}{13}$

Step 3

Move the negative in front of the fraction.

$a_{2} = - \frac{5}{13}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$a_{2} = - \frac{5}{13}$

Decimal Form:

$a_{2} = - 0.\overline{384615}$

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