Solve for a3 a_3=2(3)^(3-1)

$a_{3} = 2 {(3)}^{3 - 1}$

Step 1

Subtract $1$ from $3$ .

$a_{3} = 2 \cdot 3^{2}$

Step 2

Raise $3$ to the power of $2$ .

$a_{3} = 2 \cdot 9$

Step 3

Multiply $2$ by $9$ .

$a_{3} = 18$

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