Solve for a4 a_4=((-1)^(4+1))/(4+4)

$a_{4} = \frac{{(- 1)}^{4 + 1}}{4 + 4}$

Simplify the numerator.

Add $4$ and $1$ .

$a_{4} = \frac{{(- 1)}^{5}}{4 + 4}$

Raise $- 1$ to the power of $5$ .

$a_{4} = \frac{- 1}{4 + 4}$

$a_{4} = \frac{- 1}{4 + 4}$

Simplify the expression.

Add $4$ and $4$ .

$a_{4} = \frac{- 1}{8}$

Move the negative in front of the fraction.

$a_{4} = - \frac{1}{8}$

$a_{4} = - \frac{1}{8}$

The result can be shown in multiple forms.

Exact Form:

$a_{4} = - \frac{1}{8}$

Decimal Form:

$a_{4} = - 0.125$

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