Solve for b 1+2b-13=12-4b-2b

$1 + 2 b - 13 = 12 - 4 b - 2 b$

Since $b$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$12 - 4 b - 2 b = 1 + 2 b - 13$

Subtract $2 b$ from $- 4 b$ .

$12 - 6 b = 1 + 2 b - 13$

Subtract $13$ from $1$ .

$12 - 6 b = 2 b - 12$

Move all terms containing $b$ to the left side of the equation.

Subtract $2 b$ from both sides of the equation.

$12 - 6 b - 2 b = - 12$

Subtract $2 b$ from $- 6 b$ .

$12 - 8 b = - 12$

Move all terms not containing $b$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$- 8 b = - 12 - 12$

Subtract $12$ from $- 12$ .

$- 8 b = - 24$

Divide each term in $- 8 b = - 24$ by $- 8$ and simplify.

Divide each term in $- 8 b = - 24$ by $- 8$ .

$\frac{- 8 b}{- 8} = \frac{- 24}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 b}{- 8} = \frac{- 24}{- 8}$

Divide $b$ by $1$ .

$b = \frac{- 24}{- 8}$

Simplify the right side.

Divide $- 24$ by $- 8$ .

$b = 3$