Solve for b -12+3b-1=-5-b

$- 12 + 3 b - 1 = - 5 - b$

Step 1

Subtract $1$ from $- 12$ .

$3 b - 13 = - 5 - b$

Step 2

Move all terms containing $b$ to the left side of the equation.

Add $b$ to both sides of the equation.

$3 b - 13 + b = - 5$

Add $3 b$ and $b$ .

$4 b - 13 = - 5$

Step 3

Move all terms not containing $b$ to the right side of the equation.

Add $13$ to both sides of the equation.

$4 b = - 5 + 13$

Add $- 5$ and $13$ .

$4 b = 8$

Step 4

Divide each term in $4 b = 8$ by $4$ and simplify.

Divide each term in $4 b = 8$ by $4$ .

$\frac{4 b}{4} = \frac{8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 b}{4} = \frac{8}{4}$

Divide $b$ by $1$ .

$b = \frac{8}{4}$

Simplify the right side.

Divide $8$ by $4$ .

$b = 2$