Solve for b -14+6b+7-2b=1+5b

$- 14 + 6 b + 7 - 2 b = 1 + 5 b$

Step 1

Simplify $- 14 + 6 b + 7 - 2 b$ .

Add $- 14$ and $7$ .

$6 b - 7 - 2 b = 1 + 5 b$

Subtract $2 b$ from $6 b$ .

$4 b - 7 = 1 + 5 b$

Step 2

Move all terms containing $b$ to the left side of the equation.

Subtract $5 b$ from both sides of the equation.

$4 b - 7 - 5 b = 1$

Subtract $5 b$ from $4 b$ .

$- b - 7 = 1$

Step 3

Move all terms not containing $b$ to the right side of the equation.

Add $7$ to both sides of the equation.

$- b = 1 + 7$

Add $1$ and $7$ .

$- b = 8$

Step 4

Divide each term in $- b = 8$ by $- 1$ and simplify.

Divide each term in $- b = 8$ by $- 1$ .

$\frac{- b}{- 1} = \frac{8}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{b}{1} = \frac{8}{- 1}$

Divide $b$ by $1$ .

$b = \frac{8}{- 1}$

Simplify the right side.

Divide $8$ by $- 1$ .

$b = - 8$