Solve for b -17=-3/2b

$- 17 = - \frac{3}{2} b$

Step 1

Rewrite the equation as $- \frac{3}{2} b = - 17$ .

$- \frac{3}{2} b = - 17$

Step 2

Multiply both sides of the equation by $- \frac{2}{3}$ .

$- \frac{2}{3} (- \frac{3}{2} b) = - \frac{2}{3} \cdot - 17$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{2}{3} (- \frac{3}{2} b)$ .

Combine $b$ and $\frac{3}{2}$ .

$- \frac{2}{3} (- \frac{b \cdot 3}{2}) = - \frac{2}{3} \cdot - 17$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$\frac{- 2}{3} (- \frac{b \cdot 3}{2}) = - \frac{2}{3} \cdot - 17$

Move the leading negative in $- \frac{b \cdot 3}{2}$ into the numerator.

$\frac{- 2}{3} \cdot \frac{- b \cdot 3}{2} = - \frac{2}{3} \cdot - 17$

Factor $2$ out of $- 2$ .

$\frac{2 (- 1)}{3} \cdot \frac{- b \cdot 3}{2} = - \frac{2}{3} \cdot - 17$

Cancel the common factor.

$\frac{2 \cdot - 1}{3} \cdot \frac{- b \cdot 3}{2} = - \frac{2}{3} \cdot - 17$

Rewrite the expression.

$\frac{- 1}{3} (- b \cdot 3) = - \frac{2}{3} \cdot - 17$

Cancel the common factor of $3$ .

Factor $3$ out of $- b \cdot 3$ .

$\frac{- 1}{3} (3 \cdot (- b)) = - \frac{2}{3} \cdot - 17$

Cancel the common factor.

$\frac{- 1}{3} (3 \cdot (- b)) = - \frac{2}{3} \cdot - 17$

Rewrite the expression.

$- - b = - \frac{2}{3} \cdot - 17$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 b = - \frac{2}{3} \cdot - 17$

Multiply $b$ by $1$ .

$b = - \frac{2}{3} \cdot - 17$

Simplify the right side.

Multiply $- \frac{2}{3} \cdot - 17$ .

Multiply $- 17$ by $- 1$ .

$b = 17 (\frac{2}{3})$

Combine $17$ and $\frac{2}{3}$ .

$b = \frac{17 \cdot 2}{3}$

Multiply $17$ by $2$ .

$b = \frac{34}{3}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$b = \frac{34}{3}$

Decimal Form:

$b = 11.\overline{3}$

Mixed Number Form:

$b = 11 \frac{1}{3}$

Solve for b -17=-3/2b

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