Solve for b 2+1/6b=13

$2 + \frac{1}{6} b = 13$

Combine $\frac{1}{6}$ and $b$ .

$2 + \frac{b}{6} = 13$

Move all terms not containing $b$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$\frac{b}{6} = 13 - 2$

Subtract $2$ from $13$ .

$\frac{b}{6} = 11$

Multiply both sides of the equation by $6$ .

$6 \frac{b}{6} = 6 \cdot 11$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$6 \frac{b}{6} = 6 \cdot 11$

Rewrite the expression.

$b = 6 \cdot 11$

Simplify the right side.

Multiply $6$ by $11$ .

$b = 66$