Solve for b 2=-2/5(-3)+b

$2 = - \frac{2}{5} (- 3) + b$

Rewrite the equation as $- \frac{2}{5} \cdot - 3 + b = 2$ .

$- \frac{2}{5} \cdot - 3 + b = 2$

Multiply $- \frac{2}{5} \cdot - 3$ .

Multiply $- 3$ by $- 1$ .

$3 (\frac{2}{5}) + b = 2$

Combine $3$ and $\frac{2}{5}$ .

$\frac{3 \cdot 2}{5} + b = 2$

Multiply $3$ by $2$ .

$\frac{6}{5} + b = 2$

Move all terms not containing $b$ to the right side of the equation.

Subtract $\frac{6}{5}$ from both sides of the equation.

$b = 2 - \frac{6}{5}$

To write $2$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$b = 2 \cdot \frac{5}{5} - \frac{6}{5}$

Combine $2$ and $\frac{5}{5}$ .

$b = \frac{2 \cdot 5}{5} - \frac{6}{5}$

Combine the numerators over the common denominator.

$b = \frac{2 \cdot 5 - 6}{5}$

Simplify the numerator.

Multiply $2$ by $5$ .

$b = \frac{10 - 6}{5}$

Subtract $6$ from $10$ .

$b = \frac{4}{5}$

The result can be shown in multiple forms.

Exact Form:

$b = \frac{4}{5}$

Decimal Form:

$b = 0.8$