Solve for B 2^2+B^2=5^2

$2^{2} + B^{2} = 5^{2}$

Step 1

Raise $2$ to the power of $2$ .

$4 + B^{2} = 5^{2}$

Step 2

Raise $5$ to the power of $2$ .

$4 + B^{2} = 25$

Step 3

Move all terms not containing $B$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$B^{2} = 25 - 4$

Subtract $4$ from $25$ .

$B^{2} = 21$

Step 4

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$B = \pm \sqrt{21}$

Step 5

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$B = \sqrt{21}$

Next, use the negative value of the $\pm$ to find the second solution.

$B = - \sqrt{21}$

The complete solution is the result of both the positive and negative portions of the solution.

$B = \sqrt{21}, - \sqrt{21}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$B = \sqrt{21}, - \sqrt{21}$

Decimal Form:

$B = 4.58257569 \dots, - 4.58257569 \dots$