Solve for b -20+4b=19+12+7b

$- 20 + 4 b = 19 + 12 + 7 b$

Add $19$ and $12$ .

$- 20 + 4 b = 31 + 7 b$

Move all terms containing $b$ to the left side of the equation.

Subtract $7 b$ from both sides of the equation.

$- 20 + 4 b - 7 b = 31$

Subtract $7 b$ from $4 b$ .

$- 20 - 3 b = 31$

Move all terms not containing $b$ to the right side of the equation.

Add $20$ to both sides of the equation.

$- 3 b = 31 + 20$

Add $31$ and $20$ .

$- 3 b = 51$

Divide each term in $- 3 b = 51$ by $- 3$ and simplify.

Divide each term in $- 3 b = 51$ by $- 3$ .

$\frac{- 3 b}{- 3} = \frac{51}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 b}{- 3} = \frac{51}{- 3}$

Divide $b$ by $1$ .

$b = \frac{51}{- 3}$

Simplify the right side.

Divide $51$ by $- 3$ .

$b = - 17$