Solve for b 26+6b=2(3b+4)

$26 + 6 b = 2 (3 b + 4)$

Step 1

Simplify $2 (3 b + 4)$ .

Rewrite.

$26 + 6 b = 0 + 0 + 2 (3 b + 4)$

Simplify by adding zeros.

$26 + 6 b = 2 (3 b + 4)$

Apply the distributive property.

$26 + 6 b = 2 (3 b) + 2 \cdot 4$

Multiply.

Multiply $3$ by $2$ .

$26 + 6 b = 6 b + 2 \cdot 4$

Multiply $2$ by $4$ .

$26 + 6 b = 6 b + 8$

Step 2

Move all terms containing $b$ to the left side of the equation.

Subtract $6 b$ from both sides of the equation.

$26 + 6 b - 6 b = 8$

Combine the opposite terms in $26 + 6 b - 6 b$ .

Subtract $6 b$ from $6 b$ .

$26 + 0 = 8$

Add $26$ and $0$ .

$26 = 8$

Step 3

Since $26 \neq 8$ , there are no solutions.

No solution