Solve for b 2b+5b=28

$2 b + 5 b = 28$

Step 1

Add $2 b$ and $5 b$ .

$7 b = 28$

Step 2

Divide each term in $7 b = 28$ by $7$ and simplify.

Divide each term in $7 b = 28$ by $7$ .

$\frac{7 b}{7} = \frac{28}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 b}{7} = \frac{28}{7}$

Divide $b$ by $1$ .

$b = \frac{28}{7}$

Simplify the right side.

Divide $28$ by $7$ .

$b = 4$