Solve for b 2b+8-5b+3=-13+8b-5

$2 b + 8 - 5 b + 3 = - 13 + 8 b - 5$

Simplify $2 b + 8 - 5 b + 3$ .

Subtract $5 b$ from $2 b$ .

$- 3 b + 8 + 3 = - 13 + 8 b - 5$

Add $8$ and $3$ .

$- 3 b + 11 = - 13 + 8 b - 5$

Subtract $5$ from $- 13$ .

$- 3 b + 11 = 8 b - 18$

Move all terms containing $b$ to the left side of the equation.

Subtract $8 b$ from both sides of the equation.

$- 3 b + 11 - 8 b = - 18$

Subtract $8 b$ from $- 3 b$ .

$- 11 b + 11 = - 18$

Move all terms not containing $b$ to the right side of the equation.

Subtract $11$ from both sides of the equation.

$- 11 b = - 18 - 11$

Subtract $11$ from $- 18$ .

$- 11 b = - 29$

Divide each term in $- 11 b = - 29$ by $- 11$ and simplify.

Divide each term in $- 11 b = - 29$ by $- 11$ .

$\frac{- 11 b}{- 11} = \frac{- 29}{- 11}$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{- 11 b}{- 11} = \frac{- 29}{- 11}$

Divide $b$ by $1$ .

$b = \frac{- 29}{- 11}$

Simplify the right side.

Dividing two negative values results in a positive value.

$b = \frac{29}{11}$

The result can be shown in multiple forms.

Exact Form:

$b = \frac{29}{11}$

Decimal Form:

$b = 2.\overline{63}$

Mixed Number Form:

$b = 2 \frac{7}{11}$