Solve for b -3(33b+65)=-95b-6b-87

$- 3 (33 b + 65) = - 95 b - 6 b - 87$

Step 1

Since $b$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- 95 b - 6 b - 87 = - 3 (33 b + 65)$

Step 2

Subtract $6 b$ from $- 95 b$ .

$- 101 b - 87 = - 3 (33 b + 65)$

Step 3

Simplify $- 3 (33 b + 65)$ .

Apply the distributive property.

$- 101 b - 87 = - 3 (33 b) - 3 \cdot 65$

Multiply.

Multiply $33$ by $- 3$ .

$- 101 b - 87 = - 99 b - 3 \cdot 65$

Multiply $- 3$ by $65$ .

$- 101 b - 87 = - 99 b - 195$

Step 4

Move all terms containing $b$ to the left side of the equation.

Add $99 b$ to both sides of the equation.

$- 101 b - 87 + 99 b = - 195$

Add $- 101 b$ and $99 b$ .

$- 2 b - 87 = - 195$

Step 5

Move all terms not containing $b$ to the right side of the equation.

Add $87$ to both sides of the equation.

$- 2 b = - 195 + 87$

Add $- 195$ and $87$ .

$- 2 b = - 108$

Step 6

Divide each term in $- 2 b = - 108$ by $- 2$ and simplify.

Divide each term in $- 2 b = - 108$ by $- 2$ .

$\frac{- 2 b}{- 2} = \frac{- 108}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 b}{- 2} = \frac{- 108}{- 2}$

Divide $b$ by $1$ .

$b = \frac{- 108}{- 2}$

Simplify the right side.

Divide $- 108$ by $- 2$ .

$b = 54$