Solve for b 3(-3b+10)=-6b-10+5b

$3 (- 3 b + 10) = - 6 b - 10 + 5 b$

Step 1

Since $b$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- 6 b - 10 + 5 b = 3 (- 3 b + 10)$

Step 2

Add $- 6 b$ and $5 b$ .

$- b - 10 = 3 (- 3 b + 10)$

Step 3

Simplify $3 (- 3 b + 10)$ .

Apply the distributive property.

$- b - 10 = 3 (- 3 b) + 3 \cdot 10$

Multiply.

Multiply $- 3$ by $3$ .

$- b - 10 = - 9 b + 3 \cdot 10$

Multiply $3$ by $10$ .

$- b - 10 = - 9 b + 30$

Step 4

Move all terms containing $b$ to the left side of the equation.

Add $9 b$ to both sides of the equation.

$- b - 10 + 9 b = 30$

Add $- b$ and $9 b$ .

$8 b - 10 = 30$

Step 5

Move all terms not containing $b$ to the right side of the equation.

Add $10$ to both sides of the equation.

$8 b = 30 + 10$

Add $30$ and $10$ .

$8 b = 40$

Step 6

Divide each term in $8 b = 40$ by $8$ and simplify.

Divide each term in $8 b = 40$ by $8$ .

$\frac{8 b}{8} = \frac{40}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 b}{8} = \frac{40}{8}$

Divide $b$ by $1$ .

$b = \frac{40}{8}$

Simplify the right side.

Divide $40$ by $8$ .

$b = 5$