Solve for b -(3-6b)=6b+5

$- (3 - 6 b) = 6 b + 5$

Step 1

Simplify $- (3 - 6 b)$ .

Rewrite.

$0 + 0 - (3 - 6 b) = 6 b + 5$

Simplify by adding zeros.

$- (3 - 6 b) = 6 b + 5$

Apply the distributive property.

$- 1 \cdot 3 - (- 6 b) = 6 b + 5$

Multiply.

Multiply $- 1$ by $3$ .

$- 3 - (- 6 b) = 6 b + 5$

Multiply $- 6$ by $- 1$ .

$- 3 + 6 b = 6 b + 5$

Step 2

Move all terms containing $b$ to the left side of the equation.

Subtract $6 b$ from both sides of the equation.

$- 3 + 6 b - 6 b = 5$

Combine the opposite terms in $- 3 + 6 b - 6 b$ .

Subtract $6 b$ from $6 b$ .

$- 3 + 0 = 5$

Add $- 3$ and $0$ .

$- 3 = 5$

Step 3

Since $- 3 \neq 5$ , there are no solutions.

No solution