Solve for b 329=-7(1+6b)

$329 = - 7 (1 + 6 b)$

Rewrite the equation as $- 7 (1 + 6 b) = 329$ .

$- 7 (1 + 6 b) = 329$

Divide each term in $- 7 (1 + 6 b) = 329$ by $- 7$ and simplify.

Divide each term in $- 7 (1 + 6 b) = 329$ by $- 7$ .

$\frac{- 7 (1 + 6 b)}{- 7} = \frac{329}{- 7}$

Simplify the left side.

Cancel the common factor of $- 7$ .

Cancel the common factor.

$\frac{- 7 (1 + 6 b)}{- 7} = \frac{329}{- 7}$

Divide $1 + 6 b$ by $1$ .

$1 + 6 b = \frac{329}{- 7}$

Simplify the right side.

Divide $329$ by $- 7$ .

$1 + 6 b = - 47$

Move all terms not containing $b$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$6 b = - 47 - 1$

Subtract $1$ from $- 47$ .

$6 b = - 48$

Divide each term in $6 b = - 48$ by $6$ and simplify.

Divide each term in $6 b = - 48$ by $6$ .

$\frac{6 b}{6} = \frac{- 48}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 b}{6} = \frac{- 48}{6}$

Divide $b$ by $1$ .

$b = \frac{- 48}{6}$

Simplify the right side.

Divide $- 48$ by $6$ .

$b = - 8$