Solve for b 3b-13+4b=7b+1

$3 b - 13 + 4 b = 7 b + 1$

Step 1

Add $3 b$ and $4 b$ .

$7 b - 13 = 7 b + 1$

Step 2

Move all terms containing $b$ to the left side of the equation.

Subtract $7 b$ from both sides of the equation.

$7 b - 13 - 7 b = 1$

Combine the opposite terms in $7 b - 13 - 7 b$ .

Subtract $7 b$ from $7 b$ .

$0 - 13 = 1$

Subtract $13$ from $0$ .

$- 13 = 1$

Step 3

Since $- 13 \neq 1$ , there are no solutions.

No solution