Solve for B 3B-2=10

$3 B - 2 = 10$

Move all terms not containing $B$ to the right side of the equation.

Add $2$ to both sides of the equation.

$3 B = 10 + 2$

Add $10$ and $2$ .

$3 B = 12$

Divide each term in $3 B = 12$ by $3$ and simplify.

Divide each term in $3 B = 12$ by $3$ .

$\frac{3 B}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 B}{3} = \frac{12}{3}$

Divide $B$ by $1$ .

$B = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$B = 4$