Solve for b (3b-4)/2=c

$\frac{3 b - 4}{2} = c$

Step 1

Multiply both sides by $2$ .

$\frac{3 b - 4}{2} \cdot 2 = c \cdot 2$

Step 2

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{3 b - 4}{2} \cdot 2 = c \cdot 2$

Rewrite the expression.

$3 b - 4 = c \cdot 2$

Simplify the right side.

Move $2$ to the left of $c$ .

$3 b - 4 = 2 c$

Step 3

Solve for $b$ .

Add $4$ to both sides of the equation.

$3 b = 2 c + 4$

Divide each term in $3 b = 2 c + 4$ by $3$ and simplify.

Divide each term in $3 b = 2 c + 4$ by $3$ .

$\frac{3 b}{3} = \frac{2 c}{3} + \frac{4}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 b}{3} = \frac{2 c}{3} + \frac{4}{3}$

Divide $b$ by $1$ .

$b = \frac{2 c}{3} + \frac{4}{3}$