Solve for b |3b+9|-16=-52

$| 3 b + 9 | - 16 = - 52$

Step 1

Move all terms not containing $| 3 b + 9 |$ to the right side of the equation.

Add $16$ to both sides of the equation.

$| 3 b + 9 | = - 52 + 16$

Add $- 52$ and $16$ .

$| 3 b + 9 | = - 36$

Step 2

There is no value of $b$ that makes the equation be true since an absolute value can never be negative.

No solution