Solve for b -3f^3+1/6mb=d

$- 3 f^{3} + \frac{1}{6} m b = d$

Step 1

Multiply $\frac{1}{6} (m b)$ .

Combine $m$ and $\frac{1}{6}$ .

$- 3 f^{3} + \frac{m}{6} b = d$

Combine $\frac{m}{6}$ and $b$ .

$- 3 f^{3} + \frac{m b}{6} = d$

Step 2

Add $3 f^{3}$ to both sides of the equation.

$\frac{m b}{6} = d + 3 f^{3}$

Step 3

Multiply both sides of the equation by $6$ .

$6 \frac{m b}{6} = 6 (d + 3 f^{3})$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$6 \frac{m b}{6} = 6 (d + 3 f^{3})$

Rewrite the expression.

$m b = 6 (d + 3 f^{3})$

Simplify the right side.

Simplify $6 (d + 3 f^{3})$ .

Apply the distributive property.

$m b = 6 d + 6 (3 f^{3})$

Multiply $3$ by $6$ .

$m b = 6 d + 18 f^{3}$

Step 5

Divide each term in $m b = 6 d + 18 f^{3}$ by $m$ and simplify.

Divide each term in $m b = 6 d + 18 f^{3}$ by $m$ .

$\frac{m b}{m} = \frac{6 d}{m} + \frac{18 f^{3}}{m}$

Simplify the left side.

Cancel the common factor of $m$ .

Cancel the common factor.

$\frac{m b}{m} = \frac{6 d}{m} + \frac{18 f^{3}}{m}$

Divide $b$ by $1$ .

$b = \frac{6 d}{m} + \frac{18 f^{3}}{m}$