Solve for b 3x+3b=12

$3 x + 3 b = 12$

Step 1

Subtract $3 x$ from both sides of the equation.

$3 b = 12 - 3 x$

Step 2

Divide each term in $3 b = 12 - 3 x$ by $3$ and simplify.

Divide each term in $3 b = 12 - 3 x$ by $3$ .

$\frac{3 b}{3} = \frac{12}{3} + \frac{- 3 x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 b}{3} = \frac{12}{3} + \frac{- 3 x}{3}$

Divide $b$ by $1$ .

$b = \frac{12}{3} + \frac{- 3 x}{3}$

$b = \frac{12}{3} + \frac{- 3 x}{3}$

$b = \frac{12}{3} + \frac{- 3 x}{3}$

Simplify the right side.

Simplify each term.

Divide $12$ by $3$ .

$b = 4 + \frac{- 3 x}{3}$

Cancel the common factor of $- 3$ and $3$ .

Factor $3$ out of $- 3 x$ .

$b = 4 + \frac{3 (- x)}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$b = 4 + \frac{3 (- x)}{3 (1)}$

Cancel the common factor.

$b = 4 + \frac{3 (- x)}{3 \cdot 1}$

Rewrite the expression.

$b = 4 + \frac{- x}{1}$

Divide $- x$ by $1$ .

$b = 4 - x$

$b = 4 - x$

$b = 4 - x$

$b = 4 - x$

$b = 4 - x$

$b = 4 - x$

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