Solve for b -|4-8b|=12

$- | 4 - 8 b | = 12$

Step 1

Divide each term in $- | 4 - 8 b | = 12$ by $- 1$ and simplify.

Divide each term in $- | 4 - 8 b | = 12$ by $- 1$ .

$\frac{- | 4 - 8 b |}{- 1} = \frac{12}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{| 4 - 8 b |}{1} = \frac{12}{- 1}$

Divide $| 4 - 8 b |$ by $1$ .

$| 4 - 8 b | = \frac{12}{- 1}$

Simplify the right side.

Divide $12$ by $- 1$ .

$| 4 - 8 b | = - 12$

Step 2

There is no value of $b$ that makes the equation be true since an absolute value can never be negative.

No solution