Solve for b 4(8b-28)+8=-8(-11b-9)-8

$4 (8 b - 28) + 8 = - 8 (- 11 b - 9) - 8$

Step 1

Simplify $4 (8 b - 28) + 8$ .

Simplify each term.

Apply the distributive property.

$4 (8 b) + 4 \cdot - 28 + 8 = - 8 (- 11 b - 9) - 8$

Multiply $8$ by $4$ .

$32 b + 4 \cdot - 28 + 8 = - 8 (- 11 b - 9) - 8$

Multiply $4$ by $- 28$ .

$32 b - 112 + 8 = - 8 (- 11 b - 9) - 8$

Add $- 112$ and $8$ .

$32 b - 104 = - 8 (- 11 b - 9) - 8$

Step 2

Simplify $- 8 (- 11 b - 9) - 8$ .

Simplify each term.

Apply the distributive property.

$32 b - 104 = - 8 (- 11 b) - 8 \cdot - 9 - 8$

Multiply $- 11$ by $- 8$ .

$32 b - 104 = 88 b - 8 \cdot - 9 - 8$

Multiply $- 8$ by $- 9$ .

$32 b - 104 = 88 b + 72 - 8$

Subtract $8$ from $72$ .

$32 b - 104 = 88 b + 64$

Step 3

Move all terms containing $b$ to the left side of the equation.

Subtract $88 b$ from both sides of the equation.

$32 b - 104 - 88 b = 64$

Subtract $88 b$ from $32 b$ .

$- 56 b - 104 = 64$

Step 4

Move all terms not containing $b$ to the right side of the equation.

Add $104$ to both sides of the equation.

$- 56 b = 64 + 104$

Add $64$ and $104$ .

$- 56 b = 168$

Step 5

Divide each term in $- 56 b = 168$ by $- 56$ and simplify.

Divide each term in $- 56 b = 168$ by $- 56$ .

$\frac{- 56 b}{- 56} = \frac{168}{- 56}$

Simplify the left side.

Cancel the common factor of $- 56$ .

Cancel the common factor.

$\frac{- 56 b}{- 56} = \frac{168}{- 56}$

Divide $b$ by $1$ .

$b = \frac{168}{- 56}$

Simplify the right side.

Divide $168$ by $- 56$ .

$b = - 3$

Solve for b 4(8b-28)+8=-8(-11b-9)-8

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