Solve for b 4(b-2)-10=2(b+3)

$4 (b - 2) - 10 = 2 (b + 3)$

Simplify $4 (b - 2) - 10$ .

Simplify each term.

Apply the distributive property.

$4 b + 4 \cdot - 2 - 10 = 2 (b + 3)$

Multiply $4$ by $- 2$ .

$4 b - 8 - 10 = 2 (b + 3)$

Subtract $10$ from $- 8$ .

$4 b - 18 = 2 (b + 3)$

Simplify $2 (b + 3)$ .

Apply the distributive property.

$4 b - 18 = 2 b + 2 \cdot 3$

Multiply $2$ by $3$ .

$4 b - 18 = 2 b + 6$

Move all terms containing $b$ to the left side of the equation.

Subtract $2 b$ from both sides of the equation.

$4 b - 18 - 2 b = 6$

Subtract $2 b$ from $4 b$ .

$2 b - 18 = 6$

Move all terms not containing $b$ to the right side of the equation.

Add $18$ to both sides of the equation.

$2 b = 6 + 18$

Add $6$ and $18$ .

$2 b = 24$

Divide each term in $2 b = 24$ by $2$ and simplify.

Divide each term in $2 b = 24$ by $2$ .

$\frac{2 b}{2} = \frac{24}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 b}{2} = \frac{24}{2}$

Divide $b$ by $1$ .

$b = \frac{24}{2}$

Simplify the right side.

Divide $24$ by $2$ .

$b = 12$