Solve for b 4(b+23)=8b+23

$4 (b + 23) = 8 b + 23$

Simplify $4 (b + 23)$ .

Rewrite.

$0 + 0 + 4 (b + 23) = 8 b + 23$

Simplify by adding zeros.

$4 (b + 23) = 8 b + 23$

Apply the distributive property.

$4 b + 4 \cdot 23 = 8 b + 23$

Multiply $4$ by $23$ .

$4 b + 92 = 8 b + 23$

Move all terms containing $b$ to the left side of the equation.

Subtract $8 b$ from both sides of the equation.

$4 b + 92 - 8 b = 23$

Subtract $8 b$ from $4 b$ .

$- 4 b + 92 = 23$

Move all terms not containing $b$ to the right side of the equation.

Subtract $92$ from both sides of the equation.

$- 4 b = 23 - 92$

Subtract $92$ from $23$ .

$- 4 b = - 69$

Divide each term in $- 4 b = - 69$ by $- 4$ and simplify.

Divide each term in $- 4 b = - 69$ by $- 4$ .

$\frac{- 4 b}{- 4} = \frac{- 69}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 b}{- 4} = \frac{- 69}{- 4}$

Divide $b$ by $1$ .

$b = \frac{- 69}{- 4}$

Simplify the right side.

Dividing two negative values results in a positive value.

$b = \frac{69}{4}$

The result can be shown in multiple forms.

Exact Form:

$b = \frac{69}{4}$

Decimal Form:

$b = 17.25$

Mixed Number Form:

$b = 17 \frac{1}{4}$