Solve for b -4+bx=2x+3(x+1)

$- 4 + b x = 2 x + 3 (x + 1)$

Step 1

Simplify $2 x + 3 (x + 1)$ .

Simplify each term.

Apply the distributive property.

$- 4 + b x = 2 x + 3 x + 3 \cdot 1$

Multiply $3$ by $1$ .

$- 4 + b x = 2 x + 3 x + 3$

Add $2 x$ and $3 x$ .

$- 4 + b x = 5 x + 3$

Step 2

Move all terms not containing $b$ to the right side of the equation.

Add $4$ to both sides of the equation.

$b x = 5 x + 3 + 4$

Add $3$ and $4$ .

$b x = 5 x + 7$

Step 3

Divide each term in $b x = 5 x + 7$ by $x$ and simplify.

Divide each term in $b x = 5 x + 7$ by $x$ .

$\frac{b x}{x} = \frac{5 x}{x} + \frac{7}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{b x}{x} = \frac{5 x}{x} + \frac{7}{x}$

Divide $b$ by $1$ .

$b = \frac{5 x}{x} + \frac{7}{x}$

Simplify the right side.

Cancel the common factor of $x$ .

Cancel the common factor.

$b = \frac{5 x}{x} + \frac{7}{x}$

Divide $5$ by $1$ .

$b = 5 + \frac{7}{x}$