Solve for b (5b-4)(b+3)=0

$(5 b - 4) (b + 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$5 b - 4 = 0$

$b + 3 = 0$

Set $5 b - 4$ equal to $0$ and solve for $b$ .

Set $5 b - 4$ equal to $0$ .

$5 b - 4 = 0$

Solve $5 b - 4 = 0$ for $b$ .

Add $4$ to both sides of the equation.

$5 b = 4$

Divide each term in $5 b = 4$ by $5$ and simplify.

Divide each term in $5 b = 4$ by $5$ .

$\frac{5 b}{5} = \frac{4}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 b}{5} = \frac{4}{5}$

Divide $b$ by $1$ .

$b = \frac{4}{5}$

Set $b + 3$ equal to $0$ and solve for $b$ .

Set $b + 3$ equal to $0$ .

$b + 3 = 0$

Subtract $3$ from both sides of the equation.

$b = - 3$

The final solution is all the values that make $(5 b - 4) (b + 3) = 0$ true.

$b = \frac{4}{5}, - 3$

The result can be shown in multiple forms.

Exact Form:

$b = \frac{4}{5}, - 3$

Decimal Form:

$b = 0.8, - 3$