Solve for B 6=10B+12C

$6 = 10 B + 12 C$

Step 1

Rewrite the equation as $10 B + 12 C = 6$ .

$10 B + 12 C = 6$

Step 2

Subtract $12 C$ from both sides of the equation.

$10 B = 6 - 12 C$

Step 3

Divide each term in $10 B = 6 - 12 C$ by $10$ and simplify.

Divide each term in $10 B = 6 - 12 C$ by $10$ .

$\frac{10 B}{10} = \frac{6}{10} + \frac{- 12 C}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 B}{10} = \frac{6}{10} + \frac{- 12 C}{10}$

Divide $B$ by $1$ .

$B = \frac{6}{10} + \frac{- 12 C}{10}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $6$ and $10$ .

Factor $2$ out of $6$ .

$B = \frac{2 (3)}{10} + \frac{- 12 C}{10}$

Cancel the common factors.

Factor $2$ out of $10$ .

$B = \frac{2 \cdot 3}{2 \cdot 5} + \frac{- 12 C}{10}$

Cancel the common factor.

$B = \frac{2 \cdot 3}{2 \cdot 5} + \frac{- 12 C}{10}$

Rewrite the expression.

$B = \frac{3}{5} + \frac{- 12 C}{10}$

Cancel the common factor of $- 12$ and $10$ .

Factor $2$ out of $- 12 C$ .

$B = \frac{3}{5} + \frac{2 (- 6 C)}{10}$

Cancel the common factors.

Factor $2$ out of $10$ .

$B = \frac{3}{5} + \frac{2 (- 6 C)}{2 (5)}$

Cancel the common factor.

$B = \frac{3}{5} + \frac{2 (- 6 C)}{2 \cdot 5}$

Rewrite the expression.

$B = \frac{3}{5} + \frac{- 6 C}{5}$

Move the negative in front of the fraction.

$B = \frac{3}{5} - \frac{6 C}{5}$