Solve for b -6+5(-1-b)=19

$- 6 + 5 (- 1 - b) = 19$

Step 1

Simplify $- 6 + 5 (- 1 - b)$ .

Simplify each term.

Apply the distributive property.

$- 6 + 5 \cdot - 1 + 5 (- b) = 19$

Multiply $5$ by $- 1$ .

$- 6 - 5 + 5 (- b) = 19$

Multiply $- 1$ by $5$ .

$- 6 - 5 - 5 b = 19$

Subtract $5$ from $- 6$ .

$- 11 - 5 b = 19$

Step 2

Move all terms not containing $b$ to the right side of the equation.

Add $11$ to both sides of the equation.

$- 5 b = 19 + 11$

Add $19$ and $11$ .

$- 5 b = 30$

Step 3

Divide each term in $- 5 b = 30$ by $- 5$ and simplify.

Divide each term in $- 5 b = 30$ by $- 5$ .

$\frac{- 5 b}{- 5} = \frac{30}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 b}{- 5} = \frac{30}{- 5}$

Divide $b$ by $1$ .

$b = \frac{30}{- 5}$

Simplify the right side.

Divide $30$ by $- 5$ .

$b = - 6$