Solve for b -6/5(30b+15)-3b=-1/5b-3+6/5b

$- \frac{6}{5} (30 b + 15) - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Simplify $- \frac{6}{5} \cdot (30 b + 15) - 3 b$ .

Simplify each term.

Apply the distributive property.

$- \frac{6}{5} (30 b) - \frac{6}{5} \cdot 15 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{6}{5}$ into the numerator.

$\frac{- 6}{5} (30 b) - \frac{6}{5} \cdot 15 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Factor $5$ out of $30 b$ .

$\frac{- 6}{5} (5 (6 b)) - \frac{6}{5} \cdot 15 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Cancel the common factor.

$\frac{- 6}{5} (5 (6 b)) - \frac{6}{5} \cdot 15 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Rewrite the expression.

$- 6 (6 b) - \frac{6}{5} \cdot 15 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Multiply $6$ by $- 6$ .

$- 36 b - \frac{6}{5} \cdot 15 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{6}{5}$ into the numerator.

$- 36 b + \frac{- 6}{5} \cdot 15 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Factor $5$ out of $15$ .

$- 36 b + \frac{- 6}{5} \cdot (5 (3)) - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Cancel the common factor.

$- 36 b + \frac{- 6}{5} \cdot (5 \cdot 3) - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Rewrite the expression.

$- 36 b - 6 \cdot 3 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Multiply $- 6$ by $3$ .

$- 36 b - 18 - 3 b = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Subtract $3 b$ from $- 36 b$ .

$- 39 b - 18 = - \frac{1}{5} b - 3 + \frac{6}{5} b$

Simplify $- \frac{1}{5} b - 3 + \frac{6}{5} b$ .

Simplify each term.

Combine $b$ and $\frac{1}{5}$ .

$- 39 b - 18 = - \frac{b}{5} - 3 + \frac{6}{5} b$

Combine $\frac{6}{5}$ and $b$ .

$- 39 b - 18 = - \frac{b}{5} - 3 + \frac{6 b}{5}$

Simplify terms.

Combine the numerators over the common denominator.

$- 39 b - 18 = - 3 + \frac{- b + 6 b}{5}$

Add $- b$ and $6 b$ .

$- 39 b - 18 = - 3 + \frac{5 b}{5}$

Cancel the common factor of $5$ .

Cancel the common factor.

$- 39 b - 18 = - 3 + \frac{5 b}{5}$

Divide $b$ by $1$ .

$- 39 b - 18 = - 3 + b$

Move all terms containing $b$ to the left side of the equation.

Subtract $b$ from both sides of the equation.

$- 39 b - 18 - b = - 3$

Subtract $b$ from $- 39 b$ .

$- 40 b - 18 = - 3$

Move all terms not containing $b$ to the right side of the equation.

Add $18$ to both sides of the equation.

$- 40 b = - 3 + 18$

Add $- 3$ and $18$ .

$- 40 b = 15$

Divide each term in $- 40 b = 15$ by $- 40$ and simplify.

Divide each term in $- 40 b = 15$ by $- 40$ .

$\frac{- 40 b}{- 40} = \frac{15}{- 40}$

Simplify the left side.

Cancel the common factor of $- 40$ .

Cancel the common factor.

$\frac{- 40 b}{- 40} = \frac{15}{- 40}$

Divide $b$ by $1$ .

$b = \frac{15}{- 40}$

Simplify the right side.

Cancel the common factor of $15$ and $- 40$ .

Factor $5$ out of $15$ .

$b = \frac{5 (3)}{- 40}$

Cancel the common factors.

Factor $5$ out of $- 40$ .

$b = \frac{5 \cdot 3}{5 \cdot - 8}$

Cancel the common factor.

$b = \frac{5 \cdot 3}{5 \cdot - 8}$

Rewrite the expression.

$b = \frac{3}{- 8}$

Move the negative in front of the fraction.

$b = - \frac{3}{8}$

The result can be shown in multiple forms.

Exact Form:

$b = - \frac{3}{8}$

Decimal Form:

$b = - 0.375$

Solve for b -6/5(30b+15)-3b=-1/5b-3+6/5b

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