Solve for b -6b-6b-9=8b-9

$- 6 b - 6 b - 9 = 8 b - 9$

Step 1

Subtract $6 b$ from $- 6 b$ .

$- 12 b - 9 = 8 b - 9$

Step 2

Move all terms containing $b$ to the left side of the equation.

Subtract $8 b$ from both sides of the equation.

$- 12 b - 9 - 8 b = - 9$

Subtract $8 b$ from $- 12 b$ .

$- 20 b - 9 = - 9$

Step 3

Move all terms not containing $b$ to the right side of the equation.

Add $9$ to both sides of the equation.

$- 20 b = - 9 + 9$

Add $- 9$ and $9$ .

$- 20 b = 0$

Step 4

Divide each term in $- 20 b = 0$ by $- 20$ and simplify.

Divide each term in $- 20 b = 0$ by $- 20$ .

$\frac{- 20 b}{- 20} = \frac{0}{- 20}$

Simplify the left side.

Cancel the common factor of $- 20$ .

Cancel the common factor.

$\frac{- 20 b}{- 20} = \frac{0}{- 20}$

Divide $b$ by $1$ .

$b = \frac{0}{- 20}$

Simplify the right side.

Divide $0$ by $- 20$ .

$b = 0$