Solve for b 7=-11+3(b+5)

$7 = - 11 + 3 (b + 5)$

Step 1

Rewrite the equation as $- 11 + 3 (b + 5) = 7$ .

$- 11 + 3 (b + 5) = 7$

Step 2

Simplify $- 11 + 3 (b + 5)$ .

Simplify each term.

Apply the distributive property.

$- 11 + 3 b + 3 \cdot 5 = 7$

Multiply $3$ by $5$ .

$- 11 + 3 b + 15 = 7$

Add $- 11$ and $15$ .

$3 b + 4 = 7$

Step 3

Move all terms not containing $b$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$3 b = 7 - 4$

Subtract $4$ from $7$ .

$3 b = 3$

Step 4

Divide each term in $3 b = 3$ by $3$ and simplify.

Divide each term in $3 b = 3$ by $3$ .

$\frac{3 b}{3} = \frac{3}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 b}{3} = \frac{3}{3}$

Divide $b$ by $1$ .

$b = \frac{3}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$b = 1$