Solve for B 7B=-g^3B+h

$7 B = - g^{3} B + h$

Add $g^{3} B$ to both sides of the equation.

$7 B + g^{3} B = h$

Factor $B$ out of $7 B + g^{3} B$ .

Factor $B$ out of $7 B$ .

$B \cdot 7 + g^{3} B = h$

Factor $B$ out of $g^{3} B$ .

$B \cdot 7 + B g^{3} = h$

Factor $B$ out of $B \cdot 7 + B g^{3}$ .

$B (7 + g^{3}) = h$

Divide each term in $B (7 + g^{3}) = h$ by $7 + g^{3}$ and simplify.

Divide each term in $B (7 + g^{3}) = h$ by $7 + g^{3}$ .

$\frac{B (7 + g^{3})}{7 + g^{3}} = \frac{h}{7 + g^{3}}$

Simplify the left side.

Cancel the common factor of $7 + g^{3}$ .

Cancel the common factor.

$\frac{B (7 + g^{3})}{7 + g^{3}} = \frac{h}{7 + g^{3}}$

Divide $B$ by $1$ .

$B = \frac{h}{7 + g^{3}}$