Solve for b 7b+H=Qb

$7 b + H = Q b$

Step 1

Subtract $Q b$ from both sides of the equation.

$7 b + H - Q b = 0$

Step 2

Subtract $H$ from both sides of the equation.

$7 b - Q b = - H$

Step 3

Factor $b$ out of $7 b - Q b$ .

Factor $b$ out of $7 b$ .

$b \cdot 7 - Q b = - H$

Factor $b$ out of $- Q b$ .

$b \cdot 7 + b (- Q) = - H$

Factor $b$ out of $b \cdot 7 + b (- Q)$ .

$b (7 - Q) = - H$

Step 4

Divide each term in $b (7 - Q) = - H$ by $7 - Q$ and simplify.

Divide each term in $b (7 - Q) = - H$ by $7 - Q$ .

$\frac{b (7 - Q)}{7 - Q} = \frac{- H}{7 - Q}$

Simplify the left side.

Cancel the common factor of $7 - Q$ .

Cancel the common factor.

$\frac{b (7 - Q)}{7 - Q} = \frac{- H}{7 - Q}$

Divide $b$ by $1$ .

$b = \frac{- H}{7 - Q}$

Simplify the right side.

Move the negative in front of the fraction.

$b = - \frac{H}{7 - Q}$