Solve for b -8(2b+8)+7=-137

$- 8 (2 b + 8) + 7 = - 137$

Simplify $- 8 (2 b + 8) + 7$ .

Simplify each term.

Apply the distributive property.

$- 8 (2 b) - 8 \cdot 8 + 7 = - 137$

Multiply $2$ by $- 8$ .

$- 16 b - 8 \cdot 8 + 7 = - 137$

Multiply $- 8$ by $8$ .

$- 16 b - 64 + 7 = - 137$

Add $- 64$ and $7$ .

$- 16 b - 57 = - 137$

Move all terms not containing $b$ to the right side of the equation.

Add $57$ to both sides of the equation.

$- 16 b = - 137 + 57$

Add $- 137$ and $57$ .

$- 16 b = - 80$

Divide each term in $- 16 b = - 80$ by $- 16$ and simplify.

Divide each term in $- 16 b = - 80$ by $- 16$ .

$\frac{- 16 b}{- 16} = \frac{- 80}{- 16}$

Simplify the left side.

Cancel the common factor of $- 16$ .

Cancel the common factor.

$\frac{- 16 b}{- 16} = \frac{- 80}{- 16}$

Divide $b$ by $1$ .

$b = \frac{- 80}{- 16}$

Simplify the right side.

Divide $- 80$ by $- 16$ .

$b = 5$