Solve for b 8b^2-40b=0

$8 b^{2} - 40 b = 0$

Step 1

Factor $8 b$ out of $8 b^{2} - 40 b$ .

Factor $8 b$ out of $8 b^{2}$ .

$8 b (b) - 40 b = 0$

Factor $8 b$ out of $- 40 b$ .

$8 b (b) + 8 b (- 5) = 0$

Factor $8 b$ out of $8 b (b) + 8 b (- 5)$ .

$8 b (b - 5) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$b = 0$

$b - 5 = 0$

Step 3

Set $b$ equal to $0$ .

$b = 0$

Step 4

Set $b - 5$ equal to $0$ and solve for $b$ .

Set $b - 5$ equal to $0$ .

$b - 5 = 0$

Add $5$ to both sides of the equation.

$b = 5$

Step 5

The final solution is all the values that make $8 b (b - 5) = 0$ true.

$b = 0, 5$