Solve for b 8b+qb=F

$8 b + q b = F$

Step 1

Factor $b$ out of $8 b + q b$ .

Factor $b$ out of $8 b$ .

$b \cdot 8 + q b = F$

Factor $b$ out of $q b$ .

$b \cdot 8 + b q = F$

Factor $b$ out of $b \cdot 8 + b q$ .

$b (8 + q) = F$

Step 2

Divide each term in $b (8 + q) = F$ by $8 + q$ and simplify.

Divide each term in $b (8 + q) = F$ by $8 + q$ .

$\frac{b (8 + q)}{8 + q} = \frac{F}{8 + q}$

Simplify the left side.

Cancel the common factor of $8 + q$ .

Cancel the common factor.

$\frac{b (8 + q)}{8 + q} = \frac{F}{8 + q}$

Divide $b$ by $1$ .

$b = \frac{F}{8 + q}$