Solve for b (9b-3)/9=(5b+5)/3

$\frac{9 b - 3}{9} = \frac{5 b + 5}{3}$

Cancel the common factor of $9 b - 3$ and $9$ .

Factor $3$ out of $9 b$ .

$\frac{3 (3 b) - 3}{9} = \frac{5 b + 5}{3}$

Factor $3$ out of $- 3$ .

$\frac{3 (3 b) + 3 (- 1)}{9} = \frac{5 b + 5}{3}$

Factor $3$ out of $3 (3 b) + 3 (- 1)$ .

$\frac{3 (3 b - 1)}{9} = \frac{5 b + 5}{3}$

Cancel the common factors.

Factor $3$ out of $9$ .

$\frac{3 (3 b - 1)}{3 (3)} = \frac{5 b + 5}{3}$

Cancel the common factor.

$\frac{3 (3 b - 1)}{3 \cdot 3} = \frac{5 b + 5}{3}$

Rewrite the expression.

$\frac{3 b - 1}{3} = \frac{5 b + 5}{3}$

Multiply both sides by $3$ .

$\frac{3 b - 1}{3} \cdot 3 = \frac{5 b + 5}{3} \cdot 3$

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 b - 1}{3} \cdot 3 = \frac{5 b + 5}{3} \cdot 3$

Rewrite the expression.

$3 b - 1 = \frac{5 b + 5}{3} \cdot 3$

Simplify the right side.

Simplify $\frac{5 b + 5}{3} \cdot 3$ .

Factor $5$ out of $5 b + 5$ .

Factor $5$ out of $5 b$ .

$3 b - 1 = \frac{5 (b) + 5}{3} \cdot 3$

Factor $5$ out of $5$ .

$3 b - 1 = \frac{5 (b) + 5 (1)}{3} \cdot 3$

Factor $5$ out of $5 (b) + 5 (1)$ .

$3 b - 1 = \frac{5 (b + 1)}{3} \cdot 3$

Cancel the common factor of $3$ .

Cancel the common factor.

$3 b - 1 = \frac{5 (b + 1)}{3} \cdot 3$

Rewrite the expression.

$3 b - 1 = 5 (b + 1)$

Apply the distributive property.

$3 b - 1 = 5 b + 5 \cdot 1$

Multiply $5$ by $1$ .

$3 b - 1 = 5 b + 5$

Solve for $b$ .

Move all terms containing $b$ to the left side of the equation.

Subtract $5 b$ from both sides of the equation.

$3 b - 1 - 5 b = 5$

Subtract $5 b$ from $3 b$ .

$- 2 b - 1 = 5$

Move all terms not containing $b$ to the right side of the equation.

Add $1$ to both sides of the equation.

$- 2 b = 5 + 1$

Add $5$ and $1$ .

$- 2 b = 6$

Divide each term in $- 2 b = 6$ by $- 2$ and simplify.

Divide each term in $- 2 b = 6$ by $- 2$ .

$\frac{- 2 b}{- 2} = \frac{6}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 b}{- 2} = \frac{6}{- 2}$

Divide $b$ by $1$ .

$b = \frac{6}{- 2}$

Simplify the right side.

Divide $6$ by $- 2$ .

$b = - 3$

Solve for b (9b-3)/9=(5b+5)/3

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