Solve for b₂ A=1/2(b_1+b_2)h

$A = \frac{1}{2} (b_{1} + b_{2}) h$

Rewrite the equation as $\frac{1}{2} \cdot ((b_{1} + b_{2}) h) = A$ .

$\frac{1}{2} \cdot ((b_{1} + b_{2}) h) = A$

Multiply both sides of the equation by $2$ .

$2 (\frac{1}{2} \cdot ((b_{1} + b_{2}) h)) = 2 A$

Simplify the left side.

Simplify $2 (\frac{1}{2} \cdot ((b_{1} + b_{2}) h))$ .

Apply the distributive property.

$2 (\frac{1}{2} \cdot (b_{1} h + b_{2} h)) = 2 A$

Apply the distributive property.

$2 (\frac{1}{2} (b_{1} h) + \frac{1}{2} (b_{2} h)) = 2 A$

Multiply $\frac{1}{2} (b_{1} h)$ .

Combine $b_{1}$ and $\frac{1}{2}$ .

$2 (\frac{b_{1}}{2} h + \frac{1}{2} (b_{2} h)) = 2 A$

Combine $\frac{b_{1}}{2}$ and $h$ .

$2 (\frac{b_{1} h}{2} + \frac{1}{2} (b_{2} h)) = 2 A$

Multiply $\frac{1}{2} (b_{2} h)$ .

Combine $b_{2}$ and $\frac{1}{2}$ .

$2 (\frac{b_{1} h}{2} + \frac{b_{2}}{2} h) = 2 A$

Combine $\frac{b_{2}}{2}$ and $h$ .

$2 (\frac{b_{1} h}{2} + \frac{b_{2} h}{2}) = 2 A$

Apply the distributive property.

$2 \frac{b_{1} h}{2} + 2 \frac{b_{2} h}{2} = 2 A$

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{b_{1} h}{2} + 2 \frac{b_{2} h}{2} = 2 A$

Rewrite the expression.

$b_{1} h + 2 \frac{b_{2} h}{2} = 2 A$

Cancel the common factor of $2$ .

Cancel the common factor.

$b_{1} h + 2 \frac{b_{2} h}{2} = 2 A$

Rewrite the expression.

$b_{1} h + b_{2} h = 2 A$

Subtract $b_{1} h$ from both sides of the equation.

$b_{2} h = 2 A - b_{1} h$

Divide each term in $b_{2} h = 2 A - b_{1} h$ by $h$ and simplify.

Divide each term in $b_{2} h = 2 A - b_{1} h$ by $h$ .

$\frac{b_{2} h}{h} = \frac{2 A}{h} + \frac{- b_{1} h}{h}$

Simplify the left side.

Cancel the common factor of $h$ .

Cancel the common factor.

$\frac{b_{2} h}{h} = \frac{2 A}{h} + \frac{- b_{1} h}{h}$

Divide $b_{2}$ by $1$ .

$b_{2} = \frac{2 A}{h} + \frac{- b_{1} h}{h}$

Simplify the right side.

Cancel the common factor of $h$ .

Cancel the common factor.

$b_{2} = \frac{2 A}{h} + \frac{- b_{1} h}{h}$

Divide $- b_{1}$ by $1$ .

$b_{2} = \frac{2 A}{h} - b_{1}$

Solve for b₂ A=1/2(b_1+b_2)h

Related Questions

Support LCMGCF.com by disabling your adblocker.