Solve for b A=1/2*(h(b+B))

$A = \frac{1}{2} \cdot (h (b + B))$

Step 1

Rewrite the equation as $\frac{1}{2} \cdot (h (b + B)) = A$ .

$\frac{1}{2} \cdot (h (b + B)) = A$

Step 2

Multiply both sides of the equation by $2$ .

$2 (\frac{1}{2} \cdot (h (b + B))) = 2 A$

Step 3

Simplify the left side.

Simplify $2 (\frac{1}{2} \cdot (h (b + B)))$ .

Apply the distributive property.

$2 (\frac{1}{2} \cdot (h b + h B)) = 2 A$

Apply the distributive property.

$2 (\frac{1}{2} (h b) + \frac{1}{2} (h B)) = 2 A$

Multiply $\frac{1}{2} (h b)$ .

Combine $h$ and $\frac{1}{2}$ .

$2 (\frac{h}{2} b + \frac{1}{2} (h B)) = 2 A$

Combine $\frac{h}{2}$ and $b$ .

$2 (\frac{h b}{2} + \frac{1}{2} (h B)) = 2 A$

$2 (\frac{h b}{2} + \frac{1}{2} (h B)) = 2 A$

Multiply $\frac{1}{2} (h B)$ .

Combine $h$ and $\frac{1}{2}$ .

$2 (\frac{h b}{2} + \frac{h}{2} B) = 2 A$

Combine $\frac{h}{2}$ and $B$ .

$2 (\frac{h b}{2} + \frac{h B}{2}) = 2 A$

$2 (\frac{h b}{2} + \frac{h B}{2}) = 2 A$

Apply the distributive property.

$2 \frac{h b}{2} + 2 \frac{h B}{2} = 2 A$

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{h b}{2} + 2 \frac{h B}{2} = 2 A$

Rewrite the expression.

$h b + 2 \frac{h B}{2} = 2 A$

$h b + 2 \frac{h B}{2} = 2 A$

Cancel the common factor of $2$ .

Cancel the common factor.

$h b + 2 \frac{h B}{2} = 2 A$

Rewrite the expression.

$h b + h B = 2 A$

$h b + h B = 2 A$

$h b + h B = 2 A$

$h b + h B = 2 A$

Step 4

Subtract $h B$ from both sides of the equation.

$h b = 2 A - h B$

Step 5

Divide each term in $h b = 2 A - h B$ by $h$ and simplify.

Divide each term in $h b = 2 A - h B$ by $h$ .

$\frac{h b}{h} = \frac{2 A}{h} + \frac{- h B}{h}$

Simplify the left side.

Cancel the common factor of $h$ .

Cancel the common factor.

$\frac{h b}{h} = \frac{2 A}{h} + \frac{- h B}{h}$

Divide $b$ by $1$ .

$b = \frac{2 A}{h} + \frac{- h B}{h}$

$b = \frac{2 A}{h} + \frac{- h B}{h}$

$b = \frac{2 A}{h} + \frac{- h B}{h}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $h$ .

Cancel the common factor.

$b = \frac{2 A}{h} + \frac{- h B}{h}$

Divide $- 1 B$ by $1$ .

$b = \frac{2 A}{h} - 1 B$

$b = \frac{2 A}{h} - 1 B$

Rewrite $- 1 B$ as $- B$ .

$b = \frac{2 A}{h} - B$

$b = \frac{2 A}{h} - B$

$b = \frac{2 A}{h} - B$

$b = \frac{2 A}{h} - B$

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