Solve for b a=2(b-c)

$a = 2 (b - c)$

Step 1

Rewrite the equation as $2 (b - c) = a$ .

$2 (b - c) = a$

Step 2

Divide each term in $2 (b - c) = a$ by $2$ and simplify.

Divide each term in $2 (b - c) = a$ by $2$ .

$\frac{2 (b - c)}{2} = \frac{a}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (b - c)}{2} = \frac{a}{2}$

Divide $b - c$ by $1$ .

$b - c = \frac{a}{2}$

Step 3

Add $c$ to both sides of the equation.

$b = \frac{a}{2} + c$