Solve for B A=3(B+C)

$A = 3 (B + C)$

Step 1

Rewrite the equation as $3 (B + C) = A$ .

$3 (B + C) = A$

Step 2

Divide each term in $3 (B + C) = A$ by $3$ and simplify.

Divide each term in $3 (B + C) = A$ by $3$ .

$\frac{3 (B + C)}{3} = \frac{A}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (B + C)}{3} = \frac{A}{3}$

Divide $B + C$ by $1$ .

$B + C = \frac{A}{3}$

Step 3

Subtract $C$ from both sides of the equation.

$B = \frac{A}{3} - C$