Solve for b a=3(b+c)

$a = 3 (b + c)$

Step 1

Rewrite the equation as $3 (b + c) = a$ .

$3 (b + c) = a$

Step 2

Divide each term in $3 (b + c) = a$ by $3$ and simplify.

Divide each term in $3 (b + c) = a$ by $3$ .

$\frac{3 (b + c)}{3} = \frac{a}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (b + c)}{3} = \frac{a}{3}$

Divide $b + c$ by $1$ .

$b + c = \frac{a}{3}$

Step 3

Subtract $c$ from both sides of the equation.

$b = \frac{a}{3} - c$