Solve for b a/b+3=c

$\frac{a}{b} + 3 = c$

Subtract $3$ from both sides of the equation.

$\frac{a}{b} = c - 3$

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$b, 1, 1$

The LCM of one and any expression is the expression.

$b$

Multiply each term in $\frac{a}{b} = c - 3$ by $b$ to eliminate the fractions.

Multiply each term in $\frac{a}{b} = c - 3$ by $b$ .

$\frac{a}{b} b = c b - 3 b$

Simplify the left side.

Cancel the common factor of $b$ .

Cancel the common factor.

$\frac{a}{b} b = c b - 3 b$

Rewrite the expression.

$a = c b - 3 b$

Solve the equation.

Rewrite the equation as $c b - 3 b = a$ .

$c b - 3 b = a$

Factor $b$ out of $c b - 3 b$ .

Factor $b$ out of $c b$ .

$b c - 3 b = a$

Factor $b$ out of $- 3 b$ .

$b c + b \cdot - 3 = a$

Factor $b$ out of $b c + b \cdot - 3$ .

$b (c - 3) = a$

Divide each term in $b (c - 3) = a$ by $c - 3$ and simplify.

Divide each term in $b (c - 3) = a$ by $c - 3$ .

$\frac{b (c - 3)}{c - 3} = \frac{a}{c - 3}$

Simplify the left side.

Cancel the common factor of $c - 3$ .

Cancel the common factor.

$\frac{b (c - 3)}{c - 3} = \frac{a}{c - 3}$

Divide $b$ by $1$ .

$b = \frac{a}{c - 3}$