Solve for b (a-b)/4=L

$\frac{a - b}{4} = L$

Multiply both sides by $4$ .

$\frac{a - b}{4} \cdot 4 = L \cdot 4$

Simplify.

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{a - b}{4} \cdot 4 = L \cdot 4$

Rewrite the expression.

$a - b = L \cdot 4$

Simplify the right side.

Move $4$ to the left of $L$ .

$a - b = 4 L$

Solve for $b$ .

Subtract $a$ from both sides of the equation.

$- b = 4 L - a$

Divide each term in $- b = 4 L - a$ by $- 1$ and simplify.

Divide each term in $- b = 4 L - a$ by $- 1$ .

$\frac{- b}{- 1} = \frac{4 L}{- 1} + \frac{- a}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{b}{1} = \frac{4 L}{- 1} + \frac{- a}{- 1}$

Divide $b$ by $1$ .

$b = \frac{4 L}{- 1} + \frac{- a}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{4 L}{- 1}$ .

$b = - 1 \cdot (4 L) + \frac{- a}{- 1}$

Rewrite $- 1 \cdot (4 L)$ as $- (4 L)$ .

$b = - (4 L) + \frac{- a}{- 1}$

Multiply $4$ by $- 1$ .

$b = - 4 L + \frac{- a}{- 1}$

Dividing two negative values results in a positive value.

$b = - 4 L + \frac{a}{1}$

Divide $a$ by $1$ .

$b = - 4 L + a$