Solve for b a=bc+b

$a = b c + b$

Rewrite the equation as $b c + b = a$ .

$b c + b = a$

Factor $b$ out of $b c + b$ .

Factor $b$ out of $b c$ .

$b (c) + b = a$

Raise $b$ to the power of $1$ .

$b (c) + b = a$

Factor $b$ out of $b^{1}$ .

$b (c) + b \cdot 1 = a$

Factor $b$ out of $b (c) + b \cdot 1$ .

$b (c + 1) = a$

Divide each term in $b (c + 1) = a$ by $c + 1$ and simplify.

Divide each term in $b (c + 1) = a$ by $c + 1$ .

$\frac{b (c + 1)}{c + 1} = \frac{a}{c + 1}$

Simplify the left side.

Cancel the common factor of $c + 1$ .

Cancel the common factor.

$\frac{b (c + 1)}{c + 1} = \frac{a}{c + 1}$

Divide $b$ by $1$ .

$b = \frac{a}{c + 1}$